좌표평면과 함수

Point A is above $-3$ on the $x\text{-axis},$ so the $x\text{-coordinate}$ of the point is $-3.$ The point is to the left of $3$ on the $y\text{-axis},$ so the $y\text{-coordinate}$ of the point is $3.$ The coordinates of the point are $(-3,3).$

Point B is below $-1$ on the $x\text{-axis},$ so the $x\text{-coordinate}$ of the point is $-1.$ The point is to the left of $-3$ on the $y\text{-axis},$ so the $y\text{-coordinate}$ of the point is $-3.$ The coordinates of the point are $(-1,-3).$

Point C is above $2$ on the $x\text{-axis},$ so the $x\text{-coordinate}$ of the point is $2.$ The point is to the right of $4$ on the $y\text{-axis},$ so the $y\text{-coordinate}$ of the point is $4.$ The coordinates of the point are $(2,4).$

Point D is below $4$ on the $x-\text{axis},$ so the $x\text{-coordinate}$ of the point is $4.$ The point is to the right of $-4$ on the $y\text{-axis},$ so the $y\text{-coordinate}$ of the point is $-4.$ The coordinates of the point are $(4,-4).$