명제와 조건 연습문제 — Sundstrom, Mathematical Reasoning · 2.4절

Sundstrom, Mathematical Reasoning · 2.4절영어 원문

For each of the following statements

(1) Write the statement in the form of an English sentence that does not use the symbols for quantifiers. - (2) Write the negation of the statement in a symbolic form that does not use the negation symbol. - (3) Write the negation of the statement in the form of an English sentence that does not use the symbols for quantifiers.

$\left( \exists x \in \mathbb{Q} \right) \left( x^2 - 3x - 7 = 0 \right)$ .

정답·풀이 보기 (영어 원문)

There exists a rational number $x$ such that $x^2 - 3x - 7 = 0$ . - $(\forall x \in \mathbb{Q}) \left( x^2 - 3x - 7 \ne 0 \right)$ . - For each rational number $x$ , $x^2 - 3x - 7 \ne 0$ .

한 번 더 — 비슷한 문제Sundstrom, Mathematical Reasoning · 2.4절영어 원문

For each of the following statements

(1) Write the statement in the form of an English sentence that does not use the symbols for quantifiers. - (2) Write the negation of the statement in a symbolic form that does not use the negation symbol. - (3) Write the negation of the statement in the form of an English sentence that does not use the symbols for quantifiers.

$\left( \exists x \in \mathbb{R} \right) \left( x^2 + 1 = 0 \right)$ .

다 풀었으면 정답 확인

There exists a real number $x$ such that $x^2 + 1 = 0$ . - $(\forall x \in \mathbb{R}) \left( \text{ } x^2 + 1 \ne 0 \right)$ . - For each real number $x$ , $x^2 + 1 \ne 0$ .

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