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명제와 조건

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Sundstrom, Mathematical Reasoning · 2.4절영어 원문

Write the negation of the statement

(∀x∈Z)(∀y∈Z)(x+y=0)\left( {\forall x \in \mathbb{Z}} \right)\left( {\forall y \in \mathbb{Z}} \right)\left( {x + y = 0} \right)

in symbolic form and as a sentence written in English.

정답·풀이 보기 (영어 원문)

(∃x∈Z)(∃y∈Z)(x+y≠0)\left( {\exists x \in \mathbb{Z}} \right)\left( {\exists y \in \mathbb{Z}} \right)\left( {x + y \ne 0} \right).

There exist integers xx and yy such that x+y≠0x + y \ne 0.

한 번 더 — 비슷한 문제Sundstrom, Mathematical Reasoning · 2.4절 · 3e번영어 원문

For each of the following statements

  • Write the statement as an English sentence that does not use the symbols for quantifiers. - Write the negation of the statement in symbolic form in which the negation symbol is not used. - Write a useful negation of the statement in an English sentence that does not use the symbols for quantifiers.

(∀x∈Z)( If x2 is odd, then x is odd )\left( {\forall x \in \mathbb{Z}} \right)\left( {\text{ If } x^2 \text{ is odd, then } x\text{ is odd } } \right).

다 풀었으면 정답 확인

For each integer xx, if x2x^2 is odd, then xx is odd. The negation is (∃x∈Z)(x2 is odd and x is even )\left( \exists x \in \mathbb{Z} \right) \left( x^2 \text{ is odd and \(x\) is even } \right), which is, There exists an integer xx such that x2x^2 is odd and xx is even.

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