문제 은행 · 기초 수학 · 공통수학2 · 집합과 명제

명제의 증명과 절대부등식

먼저 혼자 풀어 보고, 풀이로 확인한 다음, 아래 「한 번 더」 문제로 이어서 연습하세요.

Sundstrom, Mathematical Reasoning · 3.3절 · 5b번영어 원문

Prove the following propositions:

For all nonzero real numbers xx and yy, if xx is rational and yy is irrational, then xyxy is irrational.

정답·풀이 보기 (영어 원문)

Use a proof by contradiction. So, we assume that there exist nonzero real numbers xx and yy such that xx is rational, yy is irrational, and xyxy is rational. Since the rational numbers are closed under division by nonzero rational numbers, this implies that xyx\dfrac{xy}{x} is a rational number. Since xyx=y\dfrac{xy}{x} = y, we conclude that yy is a rational number and this contradicts the assumption that yy is irrational.

한 번 더 — 비슷한 문제Sundstrom, Mathematical Reasoning · 3.3절 · 2a번영어 원문

Are the following statements true or false? Justify each conclusion.

For all integers aa and bb, if aa is even and bb is odd, then 44 does not divide (a2+b2)\left( a^2 + b^2 \right).

다 풀었으면 정답 확인

This statement is true. Use a proof by contradiction. So assume that there exist integers aa and bb such that aa is even, bb is odd, and 4 divides a2+b2a^2 + b^2. So there exist integers mm and nn such that

a=2m and a2+b2=4na = 2m \qquad \text{ and } \qquad a^2 + b^2 = 4n

. Substitute a=2ma = 2m into the second equation and use algebra to rewrite in the form b2=4(n−m2)b^2 = 4(n - m^2). This means that b2b^2 is even and hence, that bb is even. This is a contradiction to the assumption that bb is odd.

이 문제로 이어서 풀기
# 명제의 증명과 절대부등식증명·논술자동 분류

「명제의 증명과 절대부등식」 문제 목록으로