OpenStax Elementary Algebra · 7.2절 · 5번우리말 번역 x2+bx+c{x}^{2}+bx+cx2+bx+c 꼴의 삼항식 인수분해하기 다음 문제에서 x2+bx+c{x}^{2}+bx+cx2+bx+c 꼴의 각 삼항식을 인수분해하세요. a2+9a+20{a}^{2}+9a+20a2+9a+20 영어 원문 보기 Factor Trinomials of the Form x2+bx+c{x}^{2}+bx+cx2+bx+c In the following exercises, factor each trinomial of the form x2+bx+c{x}^{2}+bx+cx2+bx+c. a2+9a+20{a}^{2}+9a+20a2+9a+20 풀이 공책 펴기한 줄씩 식 확인답 쓰고 채점채점정답·풀이 보기(a+4)(a+5)(a+4)(a+5)(a+4)(a+5) 원본 교재 풀이(영어)(a+4)(a+5)(a+4)(a+5)(a+4)(a+5) 한 번 더 — 비슷한 문제OpenStax Elementary Algebra · 7.1절 · 16번우리말 번역인수분해하세요: x2+3x−2x−6{x}^{2}+3x-2x-6x2+3x−2x−6. 풀이 공책 펴기한 줄씩 식 확인다 풀었으면 정답 확인There is no GCF in all four terms.x2+3x −2x−6Separate into two parts.x2+3x −2x−6Factor the GCF from both parts. Be carefulwith the signs when factoring the GCF fromthe last two terms.x(x+3)−2(x+3)(x+3)(x−2)Check on your own by multiplying.\begin{array}{cccc}\text{There is no GCF in all four terms.} & & & \quad {x}^{2}+3x\,-2x-6 \\ \text{Separate into two parts.} & & & \quad \underset{}{{x}^{2}+3x}\,\underset{}{-2x-6} \\ \\ \\ \begin{array}{c}\text{Factor the GCF from both parts. Be careful} \\ \text{with the signs when factoring the GCF from} \\ \text{the last two terms.}\end{array} & & & \quad \begin{array}{c}x(x+3)-2(x+3) \\ (x+3)(x-2)\end{array} \\ \\ \\ \text{Check on your own by multiplying.} & & & \end{array}There is no GCF in all four terms.Separate into two parts.Factor the GCF from both parts. Be carefulwith the signs when factoring the GCF fromthe last two terms.Check on your own by multiplying.x2+3x−2x−6x2+3x−2x−6x(x+3)−2(x+3)(x+3)(x−2) 이 문제로 이어서 풀기 # 인수분해계산자동 분류