OpenStax Elementary Algebra · 8.1절 · 13번우리말 번역간단히 하세요: m3+8m2−4.\frac{{m}^{3}+8}{{m}^{2}-4}.m2−4m3+8. 영어 원문 보기Simplify: m3+8m2−4.\frac{{m}^{3}+8}{{m}^{2}-4}.m2−4m3+8. 풀이 공책 펴기한 줄씩 식 확인정답·풀이 보기m3+8m2−4Factor the numerator and denominator,using the formulas for sum of cubes anddifference of squares.(m+2)(m2−2m+4)(m+2)(m−2)Remove the common factor of m+2.(m+2)(m2−2m+4)(m+2)(m−2)m2−2m+4m−2\begin{array}{cccc} & & & \quad \frac{{m}^{3}+8}{{m}^{2}-4} \\ \begin{array}{c}\text{Factor the numerator and denominator,} \\ \text{using the formulas for sum of cubes and} \\ \text{difference of squares.}\end{array} & & & \quad \frac{(m+2)({m}^{2}-2m+4)}{(m+2)(m-2)} \\ \text{Remove the common factor of}\,m+2. & & & \quad \frac{(m+2)({m}^{2}-2m+4)}{(m+2)(m-2)} \\ & & & \quad \frac{{m}^{2}-2m+4}{m-2}\end{array}Factor the numerator and denominator,using the formulas for sum of cubes anddifference of squares.Remove the common factor ofm+2.m2−4m3+8(m+2)(m−2)(m+2)(m2−2m+4)(m+2)(m−2)(m+2)(m2−2m+4)m−2m2−2m+4 원본 교재 풀이(영어)m3+8m2−4Factor the numerator and denominator,using the formulas for sum of cubes anddifference of squares.(m+2)(m2−2m+4)(m+2)(m−2)Remove the common factor of m+2.(m+2)(m2−2m+4)(m+2)(m−2)m2−2m+4m−2\begin{array}{cccc} & & & \quad \frac{{m}^{3}+8}{{m}^{2}-4} \\ \begin{array}{c}\text{Factor the numerator and denominator,} \\ \text{using the formulas for sum of cubes and} \\ \text{difference of squares.}\end{array} & & & \quad \frac{(m+2)({m}^{2}-2m+4)}{(m+2)(m-2)} \\ \text{Remove the common factor of}\,m+2. & & & \quad \frac{(m+2)({m}^{2}-2m+4)}{(m+2)(m-2)} \\ & & & \quad \frac{{m}^{2}-2m+4}{m-2}\end{array}Factor the numerator and denominator,using the formulas for sum of cubes anddifference of squares.Remove the common factor ofm+2.m2−4m3+8(m+2)(m−2)(m+2)(m2−2m+4)(m+2)(m−2)(m+2)(m2−2m+4)m−2m2−2m+4 한 번 더 — 비슷한 문제OpenStax Elementary Algebra · 8.1절 · 12번우리말 번역간단히 하세요: 3b2−12b+126b2−24.\frac{3{b}^{2}-12b+12}{6{b}^{2}-24}.6b2−243b2−12b+12. 풀이 공책 펴기한 줄씩 식 확인다 풀었으면 정답 확인3b2−12b+126b2−24Factor the numerator and denominator,first factoring out the GCF.3(b2−4b+4)6(b2−4)3(b−2)(b−2)6(b+2)(b−2)Remove the common factors of b−2 and 3.3(b−2)(b−2)3⋅2(b+2)(b−2)b−22(b+2)\begin{array}{cccc} & & & \quad \frac{3{b}^{2}-12b+12}{6{b}^{2}-24} \\ \\ \\ \begin{array}{c}\text{Factor the numerator and denominator,} \\ \text{first factoring out the GCF.}\end{array} & & & \quad \frac{3({b}^{2}-4b+4)}{6({b}^{2}-4)} \\ & & & \quad \frac{3(b-2)(b-2)}{6(b+2)(b-2)} \\ \\ \\ \text{Remove the common factors of}\,b-2\,\text{and}\,3. & & & \quad \frac{3(b-2)(b-2)}{3\cdot 2(b+2)(b-2)} \\ & & & \quad \frac{b-2}{2(b+2)}\end{array}Factor the numerator and denominator,first factoring out the GCF.Remove the common factors ofb−2and3.6b2−243b2−12b+126(b2−4)3(b2−4b+4)6(b+2)(b−2)3(b−2)(b−2)3⋅2(b+2)(b−2)3(b−2)(b−2)2(b+2)b−2 이 문제로 이어서 풀기 # 유리함수계산자동 분류