OpenStax Elementary Algebra · 8.4절 · 15번우리말 번역 다음 문제에서 주어진 최소공통분모(LCD)를 분모로 갖는 동치인 유리식으로 각각 나타내세요. 23d2+14d−5,5d3d2−19d+6\frac{2}{3{d}^{2}+14d-5},\frac{5d}{3{d}^{2}-19d+6}3d2+14d−52,3d2−19d+65d LCD (3d−1)(d+5)(d−6)(3d-1)(d+5)(d-6)(3d−1)(d+5)(d−6) 영어 원문 보기 In the following exercises, write as equivalent rational expressions with the given LCD. 23d2+14d−5,5d3d2−19d+6\frac{2}{3{d}^{2}+14d-5},\frac{5d}{3{d}^{2}-19d+6}3d2+14d−52,3d2−19d+65d LCD (3d−1)(d+5)(d−6)(3d-1)(d+5)(d-6)(3d−1)(d+5)(d−6) 풀이 공책 펴기한 줄씩 식 확인정답·풀이 보기2d−12(3d−1)(d+5)(d−6),\frac{2d-12}{(3d-1)(d+5)(d-6)},(3d−1)(d+5)(d−6)2d−12, 5d2+25d(3d−1)(d+5)(d−6)\frac{5{d}^{2}+25d}{(3d-1)(d+5)(d-6)}(3d−1)(d+5)(d−6)5d2+25d 원본 교재 풀이(영어)2d−12(3d−1)(d+5)(d−6),\frac{2d-12}{(3d-1)(d+5)(d-6)},(3d−1)(d+5)(d−6)2d−12, 5d2+25d(3d−1)(d+5)(d−6)\frac{5{d}^{2}+25d}{(3d-1)(d+5)(d-6)}(3d−1)(d+5)(d−6)5d2+25d 한 번 더 — 비슷한 문제OpenStax Elementary Algebra · 8.1절 · 13번우리말 번역간단히 하세요: m3+8m2−4.\frac{{m}^{3}+8}{{m}^{2}-4}.m2−4m3+8. 풀이 공책 펴기한 줄씩 식 확인다 풀었으면 정답 확인m3+8m2−4Factor the numerator and denominator,using the formulas for sum of cubes anddifference of squares.(m+2)(m2−2m+4)(m+2)(m−2)Remove the common factor of m+2.(m+2)(m2−2m+4)(m+2)(m−2)m2−2m+4m−2\begin{array}{cccc} & & & \quad \frac{{m}^{3}+8}{{m}^{2}-4} \\ \begin{array}{c}\text{Factor the numerator and denominator,} \\ \text{using the formulas for sum of cubes and} \\ \text{difference of squares.}\end{array} & & & \quad \frac{(m+2)({m}^{2}-2m+4)}{(m+2)(m-2)} \\ \text{Remove the common factor of}\,m+2. & & & \quad \frac{(m+2)({m}^{2}-2m+4)}{(m+2)(m-2)} \\ & & & \quad \frac{{m}^{2}-2m+4}{m-2}\end{array}Factor the numerator and denominator,using the formulas for sum of cubes anddifference of squares.Remove the common factor ofm+2.m2−4m3+8(m+2)(m−2)(m+2)(m2−2m+4)(m+2)(m−2)(m+2)(m2−2m+4)m−2m2−2m+4 이 문제로 이어서 풀기 # 유리함수계산자동 분류