문제 은행 · 기초 수학 · 공통수학2 · 집합과 명제

명제의 증명과 절대부등식

대우·귀류법으로 증명하고 산술·기하평균 부등식을 활용한다

유형·난이도는 우리말 풀이가 붙은 문제는 선생님이 정했고, 나머지는 자동 분류라 다를 수 있어요. 난이도가 정해지지 않은 문제는 난이도로 거를 때 빠집니다.

89문제 · 2 / 5쪽

21.Sundstrom, Mathematical Reasoning · 3.1절 · 6b번영어 원문

Determine if each of the following statements is true or false. If a statement is true, then write a formal proof of that statement, and if it is false, then provide a counterexample that shows it is false.

For each integer aa, if there exists an integer nn such that aa divides (9n+5)(9n + 5) and aa divides (6n+1)(6n + 1), then aa divides 7.

원본 교재에 이 문제의 정답은 실려 있지 않습니다.

한 번 더 — 비슷한 문제 풀기Sundstrom, Mathematical Reasoning · 3.1절
# 명제의 증명과 절대부등식개념 확인자동 분류
22.Sundstrom, Mathematical Reasoning · 3.1절 · 6c번영어 원문

Determine if each of the following statements is true or false. If a statement is true, then write a formal proof of that statement, and if it is false, then provide a counterexample that shows it is false.

For each integer nn, if nn is odd, then 8 divides (n4+4n2+11)\left( n^4 + 4n^2 + 11 \right).

원본 교재에 이 문제의 정답은 실려 있지 않습니다.

한 번 더 — 비슷한 문제 풀기Sundstrom, Mathematical Reasoning · 3.2절 · 3a번
# 명제의 증명과 절대부등식개념 확인자동 분류
23.Sundstrom, Mathematical Reasoning · 3.1절 · 6d번영어 원문

Determine if each of the following statements is true or false. If a statement is true, then write a formal proof of that statement, and if it is false, then provide a counterexample that shows it is false.

For each integer nn, if nn is odd, then 8 divides (n4+n2+2n)\left( n^4 + n^2 + 2n \right).

원본 교재에 이 문제의 정답은 실려 있지 않습니다.

한 번 더 — 비슷한 문제 풀기Sundstrom, Mathematical Reasoning · 3.3절 · 2a번
# 명제의 증명과 절대부등식개념 확인자동 분류
24.Sundstrom, Mathematical Reasoning · 3.1절 · 13b번영어 원문

Complete the following.

Prove that if aa, bb, and cc are real numbers for which a>0a>0 and c<0c\lt 0, then one solution of the quadratic equation ax2+bx+c=0ax^2+bx+c=0 is a positive real number.

원본 교재에 이 문제의 정답은 실려 있지 않습니다.

한 번 더 — 비슷한 문제 풀기Sundstrom, Mathematical Reasoning · 3.3절 · 5a번
# 명제의 증명과 절대부등식증명·논술자동 분류
25.Sundstrom, Mathematical Reasoning · 3.1절 · 13c번영어 원문

Complete the following.

Prove that if aa, bb, and cc are real numbers, if a≠0a \ne 0, b>0b > 0 and b2<ac\dfrac{b}{2} \lt \sqrt {ac}, then the quadratic equation ax2+bx+c=0ax^2 + bx + c = 0 has no real number solution.

원본 교재에 이 문제의 정답은 실려 있지 않습니다.

한 번 더 — 비슷한 문제 풀기Sundstrom, Mathematical Reasoning · 3.2절 · 3a번
# 명제의 증명과 절대부등식증명·논술자동 분류
26.Sundstrom, Mathematical Reasoning · 3.1절 · 14번영어 원문

Let hh and kk be real numbers and let rr be a positive number. The equation for a circle whose center is at the point (h,k)\left( h, k \right) and whose radius is rr is

(x−h)2+(y−k)2=r2\left( x - h \right)^2 + \left( y - k \right)^2 = r^2

. We also know that if aa and bb are real numbers, then

  • The point (a,b)\left( a, b \right) is inside the circle if (a−h)2+(b−k)2<r2\left( a - h \right)^2 + \left( b - k \right)^2 \lt r^2. - The point (a,b)\left( a, b \right) is on the circle if (a−h)2+(b−k)2=r2\left( a - h \right)^2 + \left( b - k \right)^2 = r^2. - The point (a,b)\left( a, b \right) is outside the circle if (a−h)2+(b−k)2>r2\left( a - h \right)^2 + \left( b - k \right)^2 > r^2.

Prove that all points on or inside the circle whose equation is (x−1)2+(y−2)2=4\left( x - 1 \right)^2 + \left( y - 2 \right)^2 = 4 are inside the circle whose equation is x2+y2=26x^2 + y^2 = 26.

원본 교재에 이 문제의 정답은 실려 있지 않습니다.

한 번 더 — 비슷한 문제 풀기Sundstrom, Mathematical Reasoning · 3.1절 · 2d번
# 명제의 증명과 절대부등식증명·논술자동 분류
27.Sundstrom, Mathematical Reasoning · 3.1절 · 15a번영어 원문

Let rr be a positive real number. The equation for a circle of radius rr whose center is the origin is x2+y2=r2x^2 + y^2 = r^2.

Use implicit differentiation to determine dydx\dfrac{dy}{dx}.

원본 교재에 이 문제의 정답은 실려 있지 않습니다.

한 번 더 — 비슷한 문제 풀기Sundstrom, Mathematical Reasoning · 3.1절 · 2a번
28.Sundstrom, Mathematical Reasoning · 3.1절 · 15b번영어 원문

Let rr be a positive real number. The equation for a circle of radius rr whose center is the origin is x2+y2=r2x^2 + y^2 = r^2.

Let (a,b)\left(a, b \right) be a point on the circle with a≠0a \ne 0 and b≠0b \ne 0. Determine the slope of the line tangent to the circle at the point (a,b)\left(a, b \right).

원본 교재에 이 문제의 정답은 실려 있지 않습니다.

한 번 더 — 비슷한 문제 풀기Sundstrom, Mathematical Reasoning · 3.1절
29.Sundstrom, Mathematical Reasoning · 3.1절 · 15c번영어 원문

Let rr be a positive real number. The equation for a circle of radius rr whose center is the origin is x2+y2=r2x^2 + y^2 = r^2.

Prove that the radius of the circle to the point (a,b)\left(a, b \right) is perpendicular to the line tangent to the circle at the point (a,b)\left(a, b \right).

Hint: Two lines (neither of which is horizontal) are perpendicular if and only if the products of their slopes is equal to

-1

.

원본 교재에 이 문제의 정답은 실려 있지 않습니다.

한 번 더 — 비슷한 문제 풀기Sundstrom, Mathematical Reasoning · 3.1절 · 2d번
# 명제의 증명과 절대부등식증명·논술자동 분류
30.Sundstrom, Mathematical Reasoning · 3.1절 · 16a번영어 원문

Determine if each of the following statements is true or false. Provide a counterexample for statements that are false and provide a complete proof for those that are true.

For all real numbers xx and yy, xy≤x+y2\sqrt{xy} \leq \dfrac{x + y}{2}.

원본 교재에 이 문제의 정답은 실려 있지 않습니다.

한 번 더 — 비슷한 문제 풀기Sundstrom, Mathematical Reasoning · 3.3절 · 11a번
# 명제의 증명과 절대부등식개념 확인자동 분류
31.Sundstrom, Mathematical Reasoning · 3.1절 · 16b번영어 원문

Determine if each of the following statements is true or false. Provide a counterexample for statements that are false and provide a complete proof for those that are true.

For all real numbers xx and yy, xy≤(x+y2)2xy \leq \left( \dfrac{x + y}{2} \right)^2.

원본 교재에 이 문제의 정답은 실려 있지 않습니다.

한 번 더 — 비슷한 문제 풀기Sundstrom, Mathematical Reasoning · 3.1절 · 2d번
# 명제의 증명과 절대부등식개념 확인자동 분류
32.Sundstrom, Mathematical Reasoning · 3.1절 · 16c번영어 원문

Determine if each of the following statements is true or false. Provide a counterexample for statements that are false and provide a complete proof for those that are true.

For all nonnegative real numbers xx and yy, xy≤x+y2\sqrt{xy} \leq \dfrac{x + y}{2}.

원본 교재에 이 문제의 정답은 실려 있지 않습니다.

한 번 더 — 비슷한 문제 풀기Sundstrom, Mathematical Reasoning · 3.1절
# 명제의 증명과 절대부등식개념 확인자동 분류
33.Sundstrom, Mathematical Reasoning · 3.1절 · 19a번영어 원문

This type of exercise will appear frequently in the book. In each case, there is a proposed proof of a proposition. However, the proposition may be true or may be false.

  • If a proposition is false, the proposed proof is, of course, incorrect. In this situation, you are to find the error in the proof and then provide a counterexample showing that the proposition is false. - If a proposition is true, the proposed proof may still be incorrect. In this case, you are to determine why the proof is incorrect and then write a correct proof using the writing guidelines that have been presented in this book. - If a proposition is true and the proof is correct, you are to decide if the proof is well written or not. If it is well written, then you simply must indicate that this is an excellent proof and needs no revision. On the other hand, if the proof is not well written, then you must then revise the proof by writing it according to the guidelines presented in this text.
  • Proposition If mm is an even integer, then (5m+4)\left(5m + 4\right) is an even integer. - Proof We see that 5m+4=10n+4=2(5n+2)5m + 4 = 10n + 4 = 2 \left(5n + 2 \right). Therefore, (5m+4)\left(5m + 4 \right) is an even integer.

원본 교재에 이 문제의 정답은 실려 있지 않습니다.

한 번 더 — 비슷한 문제 풀기Sundstrom, Mathematical Reasoning · 3.2절 · 3a번
34.Sundstrom, Mathematical Reasoning · 3.1절 · 19b번영어 원문

This type of exercise will appear frequently in the book. In each case, there is a proposed proof of a proposition. However, the proposition may be true or may be false.

  • If a proposition is false, the proposed proof is, of course, incorrect. In this situation, you are to find the error in the proof and then provide a counterexample showing that the proposition is false. - If a proposition is true, the proposed proof may still be incorrect. In this case, you are to determine why the proof is incorrect and then write a correct proof using the writing guidelines that have been presented in this book. - If a proposition is true and the proof is correct, you are to decide if the proof is well written or not. If it is well written, then you simply must indicate that this is an excellent proof and needs no revision. On the other hand, if the proof is not well written, then you must then revise the proof by writing it according to the guidelines presented in this text.
  • Proposition For all real numbers xx and yy, if x≠yx \ne y, x>0x > 0, and y>0y >0, then xy+yx>2\dfrac{x}{y} + \dfrac{y}{x} > 2. - Proof Since xx and yy are positive real numbers, xyxy is positive and we can multiply both sides of the inequality by xyxy to obtain (xy+yx)⋅xy>2⋅xyx2+y2>2xy\begin{aligned}\left( \frac{x}{y} + \frac{y}{x} \right) \cdot xy & > 2 \cdot xy \\ x^2 + y^2 & > 2xy\end{aligned} . By combining all terms on the left side of the inequality, we see that x2−2xy+y2>0x^2 - 2xy + y^2 > 0 and then by factoring the left side, we obtain (x−y)2>0\left( x - y \right)^2 > 0. Since x≠yx \ne y, (x−y)≠0\left(x - y \right) \ne 0 and so (x−y)2>0\left( x - y \right)^2 > 0. This proves that if x≠yx \ne y, x>0x > 0, and y>0y >0, then xy+yx>2\dfrac{x}{y} + \dfrac{y}{x} > 2.

원본 교재에 이 문제의 정답은 실려 있지 않습니다.

한 번 더 — 비슷한 문제 풀기Sundstrom, Mathematical Reasoning · 3.3절 · 6b번
35.Sundstrom, Mathematical Reasoning · 3.1절 · 19c번영어 원문

This type of exercise will appear frequently in the book. In each case, there is a proposed proof of a proposition. However, the proposition may be true or may be false.

  • If a proposition is false, the proposed proof is, of course, incorrect. In this situation, you are to find the error in the proof and then provide a counterexample showing that the proposition is false. - If a proposition is true, the proposed proof may still be incorrect. In this case, you are to determine why the proof is incorrect and then write a correct proof using the writing guidelines that have been presented in this book. - If a proposition is true and the proof is correct, you are to decide if the proof is well written or not. If it is well written, then you simply must indicate that this is an excellent proof and needs no revision. On the other hand, if the proof is not well written, then you must then revise the proof by writing it according to the guidelines presented in this text.
  • Proposition For all integers aa, bb, and cc, if a∣(bc)a \mid \left( bc \right), then a∣ba \mid b or a∣ca \mid c. - Proof We assume that aa, bb, and cc are integers and that aa divides bcbc. So, there exists an integer kk such that bc=kabc = ka. We now factor kk as k=mnk = mn, where mm and nn are integers. We then see that bc=mnabc = mna . This means that b=mab = ma or c=nac = na and hence, a∣ba \mid b or a∣ca \mid c.

원본 교재에 이 문제의 정답은 실려 있지 않습니다.

한 번 더 — 비슷한 문제 풀기Sundstrom, Mathematical Reasoning · 3.1절 · 3g번
36.Sundstrom, Mathematical Reasoning · 3.1절 · 19d번영어 원문

This type of exercise will appear frequently in the book. In each case, there is a proposed proof of a proposition. However, the proposition may be true or may be false.

  • If a proposition is false, the proposed proof is, of course, incorrect. In this situation, you are to find the error in the proof and then provide a counterexample showing that the proposition is false. - If a proposition is true, the proposed proof may still be incorrect. In this case, you are to determine why the proof is incorrect and then write a correct proof using the writing guidelines that have been presented in this book. - If a proposition is true and the proof is correct, you are to decide if the proof is well written or not. If it is well written, then you simply must indicate that this is an excellent proof and needs no revision. On the other hand, if the proof is not well written, then you must then revise the proof by writing it according to the guidelines presented in this text.
  • Proposition For all positive integers aa, bb, and cc, (ab)c=a(bc)\left( a^b \right)^c = a^{\left( b^c \right)}. - Proof This proposition is false as is shown by the following counterexample: If we let a=2a = 2, b=3b = 3, and c=2c = 2, then (ab)c=a(bc)(23)2=2(32)82=2964≠512\begin{aligned}\left( a^b \right)^c & = a^{\left( b^c \right)} \\ \left( 2^3 \right)^2 & = 2^{\left( 3^2 \right)} \\ 8^2 & = 2^9 \\ 64 & \ne 512\end{aligned} .

원본 교재에 이 문제의 정답은 실려 있지 않습니다.

한 번 더 — 비슷한 문제 풀기Sundstrom, Mathematical Reasoning · 3.3절 · 11a번
37.Sundstrom, Mathematical Reasoning · 3.2절영어 원문

In English, write the contrapositive of, “For all real numbers aa and bb, if a≠0a \ne 0 and b≠0b \ne 0, then ab≠0ab \ne 0.”

정답·풀이 보기 (영어 원문)

For all real numbers aa and bb, if ab=0ab = 0, then a=0 or b=0a = 0\text{ or } b = 0.

한 번 더 — 비슷한 문제 풀기Sundstrom, Mathematical Reasoning · 3.2절 · 8c번
38.Sundstrom, Mathematical Reasoning · 3.2절 · 1a번영어 원문

Let nn be an integer. Prove each of the following:

If nn is even, then n3n^3 is even.

Hint: Let nn be an even integer. Since nn is even, there exists an integer kk such that n=2kn = 2k. Now use this to prove that n3n^3 must be even.

원본 교재에 이 문제의 정답은 실려 있지 않습니다.

한 번 더 — 비슷한 문제 풀기Sundstrom, Mathematical Reasoning · 3.3절 · 3a번
# 명제의 증명과 절대부등식증명·논술자동 분류
39.Sundstrom, Mathematical Reasoning · 3.2절 · 1b번영어 원문

Let nn be an integer. Prove each of the following:

If n3n^3 is even, then nn is even.

Hint: Prove the contrapositive.

원본 교재에 이 문제의 정답은 실려 있지 않습니다.

한 번 더 — 비슷한 문제 풀기Sundstrom, Mathematical Reasoning · 3.1절 · 3b번
# 명제의 증명과 절대부등식증명·논술자동 분류
40.Sundstrom, Mathematical Reasoning · 3.2절 · 3a번영어 원문

Complete the following.

Write the contrapositive of the following statement: For all positive real numbers aa and bb, if ab≠a+b2\sqrt {ab} \ne \dfrac{{a + b}}{2}, then a≠ba \ne b.

정답·풀이 보기 (영어 원문)

The contrapositive is: For all positive real numbers aa and bb, if a=ba = b, then ab=a+b2\sqrt{ab} = \dfrac{a + b}{2}.

한 번 더 — 비슷한 문제 풀기Sundstrom, Mathematical Reasoning · 3.2절