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집합과 명제 전체 문제

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459문제 · 10 / 23쪽

181.Sundstrom, Mathematical Reasoning · 2.3절 · 6a번영어 원문

For each of the following sets, use English to describe the set and when appropriate, use the roster method to specify all of the elements of the set.

{x∈R∣−3≤x≤5}\left\{ \left. x \in \mathbb{R} \right| -3 \leq x \leq 5 \right\}

원본 교재에 이 문제의 정답은 실려 있지 않습니다.

한 번 더 — 비슷한 문제 풀기Sundstrom, Mathematical Reasoning · 5.1절
182.Sundstrom, Mathematical Reasoning · 2.3절 · 6b번영어 원문

For each of the following sets, use English to describe the set and when appropriate, use the roster method to specify all of the elements of the set.

{x∈Z∣−3≤x≤5}\left\{ \left. x \in \mathbb{Z} \right| -3 \leq x \leq 5 \right\}

원본 교재에 이 문제의 정답은 실려 있지 않습니다.

한 번 더 — 비슷한 문제 풀기Sundstrom, Mathematical Reasoning · 5.1절 · 3g번
183.Sundstrom, Mathematical Reasoning · 2.3절 · 6c번영어 원문

For each of the following sets, use English to describe the set and when appropriate, use the roster method to specify all of the elements of the set.

{x∈R∣x2=16}\left\{ \left. x \in \mathbb{R} \right| x^2 = 16 \right\}

원본 교재에 이 문제의 정답은 실려 있지 않습니다.

한 번 더 — 비슷한 문제 풀기Sundstrom, Mathematical Reasoning · 2.3절 · 5c번
184.Sundstrom, Mathematical Reasoning · 2.3절 · 6d번영어 원문

For each of the following sets, use English to describe the set and when appropriate, use the roster method to specify all of the elements of the set.

{x∈R∣x2+16=0}\left\{ \left. x \in \mathbb{R} \right| x^2 + 16 = 0 \right\}

원본 교재에 이 문제의 정답은 실려 있지 않습니다.

한 번 더 — 비슷한 문제 풀기Sundstrom, Mathematical Reasoning · 5.1절 · 3k번
185.Sundstrom, Mathematical Reasoning · 2.3절 · 6e번영어 원문

For each of the following sets, use English to describe the set and when appropriate, use the roster method to specify all of the elements of the set.

{x∈Z∣x is odd }\left\{ \left. x \in \mathbb{Z} \right| x \text{ is odd } \right\}

원본 교재에 이 문제의 정답은 실려 있지 않습니다.

한 번 더 — 비슷한 문제 풀기Sundstrom, Mathematical Reasoning · 5.2절 · 12a번
186.Sundstrom, Mathematical Reasoning · 2.3절 · 6f번영어 원문

For each of the following sets, use English to describe the set and when appropriate, use the roster method to specify all of the elements of the set.

{x∈R∣3x−4≥17}\left\{ \left. x \in \mathbb{R} \right| 3x - 4 \geq 17 \right\}

원본 교재에 이 문제의 정답은 실려 있지 않습니다.

한 번 더 — 비슷한 문제 풀기Sundstrom, Mathematical Reasoning · 5.2절
187.Sundstrom, Mathematical Reasoning · 2.4절영어 원문

For each of the following statements

  • (1) Write the statement in the form of an English sentence that does not use the symbols for quantifiers. - (2) Write the negation of the statement in a symbolic form that does not use the negation symbol. - (3) Write the negation of the statement in the form of an English sentence that does not use the symbols for quantifiers.

(∀a∈R)(a+0=a)\left( \forall a \in \mathbb{R}\right) \left( a + 0 = a \right).

정답·풀이 보기 (영어 원문)
  • For each real number aa, a+0=aa + 0 = a. - (∃a∈R)(a+0≠a)(\exists a \in \mathbb{R})( a + 0 \ne a). - There exists a real number aa such that a+0≠aa + 0 \ne a.
한 번 더 — 비슷한 문제 풀기Sundstrom, Mathematical Reasoning · 2.4절 · 2f번
# 명제와 조건계산자동 분류
188.Sundstrom, Mathematical Reasoning · 2.4절영어 원문

For each of the following statements

  • (1) Write the statement in the form of an English sentence that does not use the symbols for quantifiers. - (2) Write the negation of the statement in a symbolic form that does not use the negation symbol. - (3) Write the negation of the statement in the form of an English sentence that does not use the symbols for quantifiers.

(∀x∈R)[sin⁡(2x)=2(sin⁡x)(cos⁡x)]\left( \forall x \in \mathbb{R} \right) \left[ \sin ( {2x} ) = 2 ( {\sin x} ) ( {\cos x} ) \right].

정답·풀이 보기 (영어 원문)
  • For each real number xx, sin⁡(2x)=2(sin⁡x)(cos⁡x)\sin ( {2x} ) = 2( {\sin x} )( {\cos x} ). - (∃x∈R)(sin⁡(2x)≠2(sin⁡x)(cos⁡x))(\exists x \in \mathbb{R})( \sin ( {2x} ) \ne 2( {\sin x} )( {\cos x} )). - There exists a real number xx such that sin⁡(2x)≠2(sin⁡x)(cos⁡x)\sin \left( {2x} \right) \ne 2\left( {\sin x} \right)\left( {\cos x} \right).
한 번 더 — 비슷한 문제 풀기Sundstrom, Mathematical Reasoning · 2.4절 · 4e번
# 명제와 조건계산자동 분류
189.Sundstrom, Mathematical Reasoning · 2.4절영어 원문

For each of the following statements

  • (1) Write the statement in the form of an English sentence that does not use the symbols for quantifiers. - (2) Write the negation of the statement in a symbolic form that does not use the negation symbol. - (3) Write the negation of the statement in the form of an English sentence that does not use the symbols for quantifiers.

(∀x∈R)(tan⁡2x+1=sec⁡2x)\left( \forall x \in \mathbb{R} \right) \left( \tan ^2 x + 1 = \sec ^2 x \right).

정답·풀이 보기 (영어 원문)
  • For each real number xx, tan⁡2x+1=sec⁡2x\tan ^2 x + 1 = \sec ^2 x. - (∃x∈R)(tan⁡2x+1≠sec⁡2x)\left( \exists x \in \mathbb{R}\right) \left( \tan ^2 x + 1 \ne \sec ^2 x \right). - There exists a real number xx such that tan⁡2x+1≠sec⁡2x\tan ^2 x + 1 \ne \sec ^2 x.
한 번 더 — 비슷한 문제 풀기Sundstrom, Mathematical Reasoning · 2.4절
# 명제와 조건계산자동 분류
190.Sundstrom, Mathematical Reasoning · 2.4절영어 원문

For each of the following statements

  • (1) Write the statement in the form of an English sentence that does not use the symbols for quantifiers. - (2) Write the negation of the statement in a symbolic form that does not use the negation symbol. - (3) Write the negation of the statement in the form of an English sentence that does not use the symbols for quantifiers.

(∃x∈Q)(x2−3x−7=0)\left( \exists x \in \mathbb{Q} \right) \left( x^2 - 3x - 7 = 0 \right).

정답·풀이 보기 (영어 원문)
  • There exists a rational number xx such that x2−3x−7=0x^2 - 3x - 7 = 0. - (∀x∈Q)(x2−3x−7≠0)(\forall x \in \mathbb{Q}) \left( x^2 - 3x - 7 \ne 0 \right). - For each rational number xx, x2−3x−7≠0x^2 - 3x - 7 \ne 0.
한 번 더 — 비슷한 문제 풀기Sundstrom, Mathematical Reasoning · 2.4절
# 명제와 조건계산자동 분류
191.Sundstrom, Mathematical Reasoning · 2.4절영어 원문

For each of the following statements

  • (1) Write the statement in the form of an English sentence that does not use the symbols for quantifiers. - (2) Write the negation of the statement in a symbolic form that does not use the negation symbol. - (3) Write the negation of the statement in the form of an English sentence that does not use the symbols for quantifiers.

(∃x∈R)(x2+1=0)\left( \exists x \in \mathbb{R} \right) \left( x^2 + 1 = 0 \right).

정답·풀이 보기 (영어 원문)
  • There exists a real number xx such that x2+1=0x^2 + 1 = 0. - (∀x∈R)( x2+1≠0)(\forall x \in \mathbb{R}) \left( \text{ } x^2 + 1 \ne 0 \right). - For each real number xx, x2+1≠0x^2 + 1 \ne 0.
한 번 더 — 비슷한 문제 풀기Sundstrom, Mathematical Reasoning · 2.4절 · 2b번
# 명제와 조건계산자동 분류
192.Sundstrom, Mathematical Reasoning · 2.4절영어 원문

Use counterexamples to explain why each of the following statements is false.

For each integer nn, (n2+n+1)\left( n^2 + n + 1 \right) is a prime number.

정답·풀이 보기 (영어 원문)

A counterexample is n=4n = 4 since 42+4+1=214^2 + 4 + 1 = 21, and 21 is not prime.

한 번 더 — 비슷한 문제 풀기Sundstrom, Mathematical Reasoning · 2.3절
# 명제와 조건계산자동 분류
193.Sundstrom, Mathematical Reasoning · 2.4절영어 원문

Use counterexamples to explain why each of the following statements is false.

For each real number xx, if xx is positive, then 2x2>x2x^2 > x.

정답·풀이 보기 (영어 원문)

A counterexample is x=14x = \dfrac{1}{4} since 14\dfrac{1}{4} is positive and 2(14)2=182 \left( \dfrac{1}{4} \right)^2 = \dfrac{1}{8} and 18≤14\dfrac{1}{8} \leq \dfrac{1}{4}.

한 번 더 — 비슷한 문제 풀기Sundstrom, Mathematical Reasoning · 2.4절
# 명제와 조건계산자동 분류
194.Sundstrom, Mathematical Reasoning · 2.4절영어 원문

An integer nn is a multiple of 3 provided that there exists an integer kk such that n=3kn = 3k.

Write this definition in symbolic form using quantifiers by completing the following:

An integer

n

is a multiple of 3 provided that

.

정답·풀이 보기 (영어 원문)

An integer nn is a multiple of 3 provided that (∃k∈Z)(n=3k)\left( \exists k \in \mathbb{Z} \right) \left( n = 3k \right).

한 번 더 — 비슷한 문제 풀기Sundstrom, Mathematical Reasoning · 2.1절 · 7번
# 명제와 조건계산자동 분류
195.Sundstrom, Mathematical Reasoning · 2.4절영어 원문

An integer nn is a multiple of 3 provided that there exists an integer kk such that n=3kn = 3k.

Give several examples of integers (including negative integers) that are multiples of 3.

원본 교재에 이 문제의 정답은 실려 있지 않습니다.

한 번 더 — 비슷한 문제 풀기Sundstrom, Mathematical Reasoning · 2.4절 · 4e번
# 명제와 조건계산자동 분류
196.Sundstrom, Mathematical Reasoning · 2.4절영어 원문

An integer nn is a multiple of 3 provided that there exists an integer kk such that n=3kn = 3k.

Give several examples of integers (including negative integers) that are not multiples of 3.

원본 교재에 이 문제의 정답은 실려 있지 않습니다.

한 번 더 — 비슷한 문제 풀기Sundstrom, Mathematical Reasoning · 1.1절
# 명제와 조건계산자동 분류
197.Sundstrom, Mathematical Reasoning · 2.4절영어 원문

An integer nn is a multiple of 3 provided that there exists an integer kk such that n=3kn = 3k.

Use the symbolic form of the definition of a multiple of 3 to complete the following sentence: “An integer nn is not a multiple of 3 provided that ….”

정답·풀이 보기 (영어 원문)

An integer nn is not a multiple of 3 provided that (∀k∈Z)(n≠3k)\left( \forall k \in \mathbb{Z} \right) \left( n \ne 3k \right).

한 번 더 — 비슷한 문제 풀기Sundstrom, Mathematical Reasoning · 2.4절
# 명제와 조건계산자동 분류
198.Sundstrom, Mathematical Reasoning · 2.4절영어 원문

An integer nn is a multiple of 3 provided that there exists an integer kk such that n=3kn = 3k.

Without using the symbols for quantifiers, complete the following sentence: “An integer nn is not a multiple of 3 provided that ….”

정답·풀이 보기 (영어 원문)

An integer nn is not a multiple of 3 provided that for every integer kk, n≠3kn \ne 3k.

한 번 더 — 비슷한 문제 풀기Sundstrom, Mathematical Reasoning · 2.4절 · 6e번
# 명제와 조건계산자동 분류
199.Sundstrom, Mathematical Reasoning · 2.4절영어 원문

Write the negation of the statement

(∀x∈Z)(∀y∈Z)(x+y=0)\left( {\forall x \in \mathbb{Z}} \right)\left( {\forall y \in \mathbb{Z}} \right)\left( {x + y = 0} \right)

in symbolic form and as a sentence written in English.

정답·풀이 보기 (영어 원문)

(∃x∈Z)(∃y∈Z)(x+y≠0)\left( {\exists x \in \mathbb{Z}} \right)\left( {\exists y \in \mathbb{Z}} \right)\left( {x + y \ne 0} \right).

There exist integers xx and yy such that x+y≠0x + y \ne 0.

한 번 더 — 비슷한 문제 풀기Sundstrom, Mathematical Reasoning · 2.4절 · 3e번
# 명제와 조건계산자동 분류
200.Sundstrom, Mathematical Reasoning · 2.4절 · 1a번영어 원문

For each of the following, write the statement as an English sentence and then explain why the statement is false.

(∃x∈Q)(x2−3x−7=0)\left(\exists x \in \mathbb{Q} \right) \left( x^2 - 3x - 7 = 0 \right).

정답·풀이 보기 (영어 원문)

There exists a rational number xx such that x2−3x−7=0x^2 - 3x - 7 = 0. This statement is false since the solutions of the equation are x=3±372x = \dfrac{3 \pm \sqrt{37}}{2}, which are irrational numbers.

한 번 더 — 비슷한 문제 풀기Sundstrom, Mathematical Reasoning · 2.4절
# 명제와 조건계산자동 분류