집합과 명제 전체 문제

Let $A$, $B$, and $C$ be subsets of some universal set $U$. Draw a Venn diagram for each of the following situations.

$A \cap B = \emptyset$

Let $A$, $B$, and $C$ be subsets of some universal set $U$. Draw a Venn diagram for each of the following situations.

$A \not \subseteq B,B \not \subseteq A,C \subseteq A,\text{ and } C \not \subseteq B$

Let $A$, $B$, and $C$ be subsets of some universal set $U$. Draw a Venn diagram for each of the following situations.

$A \subseteq B,C \subseteq B,\text{ and } A \cap C = \emptyset$

Let $A$, $B$, and $C$ be subsets of some universal set $U$. For each of the following, draw a general Venn diagram for the three sets and then shade the indicated region.

$A \cap B$

Let $A$, $B$, and $C$ be subsets of some universal set $U$. For each of the following, draw a general Venn diagram for the three sets and then shade the indicated region.

$A \cap C$

Let $A$, $B$, and $C$ be subsets of some universal set $U$. For each of the following, draw a general Venn diagram for the three sets and then shade the indicated region.

$\left( {A \cap B} \right) \cup \left( {A \cap C} \right)$

Let $A$, $B$, and $C$ be subsets of some universal set $U$. For each of the following, draw a general Venn diagram for the three sets and then shade the indicated region.

$B \cup C$

Let $A$, $B$, and $C$ be subsets of some universal set $U$. For each of the following, draw a general Venn diagram for the three sets and then shade the indicated region.

$A \cap \left( {B \cup C} \right)$

Let $A$, $B$, and $C$ be subsets of some universal set $U$. For each of the following, draw a general Venn diagram for the three sets and then shade the indicated region.

$\left( {A \cap B} \right) - C$

One of the properties of real numbers is the so-called Law of Trichotomy,

which states that if $a, b \in \mathbb{R}$, then exactly one of the following is true:

• $a \lt b$; - $a = b$; - $a > b$.

Is the following proposition concerning sets true or false? Either provide a proof that it is true or a counterexample showing it is false. If $A$ and $B$ are subsets of some universal set, then exactly one of the following is true:

• $A \subseteq B$; - $A = B$; - $B \subseteq A$.

Let $A = \left\{ x \in \mathbb{Z} \mid x \text{ is a multiple of 9 } \right\}$ and let $B = \left\{ x \in \mathbb{Z} \mid x \text{ is a multiple of 3 } \right\}$.

Is the set $A$ a subset of $B$? Justify your conclusion.

Let $A = \left\{ x \in \mathbb{Z} \mid x \text{ is a multiple of 9 } \right\}$ and let $B = \left\{ x \in \mathbb{Z} \mid x \text{ is a multiple of 3 } \right\}$.

Is the set $A$ equal to the set $B$? Justify your conclusion.

Prove the following proposition. To do so, prove each set is a subset of the other set by using the choose-an-element method.

Let $A$ and $B$ be subsets of some universal set. Then $A - B = A \cap B^c$.

Let $A = \left\{ {\left. {x \in \mathbb{R}} \right| x^2 \lt 4} \right\}$ and let $B = \left\{ {x \in \mathbb{R}\left. \right| x \lt 2} \right\}$.

Is $A \subseteq B$? Justify your conclusion with a proof or a counterexample.

Let $A = \left\{ {\left. {x \in \mathbb{R}} \right| x^2 \lt 4} \right\}$ and let $B = \left\{ {x \in \mathbb{R}\left. \right| x \lt 2} \right\}$.

Is $B \subseteq A$? Justify your conclusion with a proof or a counterexample.

Let $A$, $B$, and $C$ be subsets of a universal set $U$.

Draw a Venn diagram with $A \subseteq B$ and $B \subseteq C$. Does it appear that $A \subseteq C$?

Let $A$, $B$, and $C$ be subsets of a universal set $U$.

Prove the following proposition:

If

A \subseteq B

and

B \subseteq C

, then

A \subseteq C

.

Note: This may seem like an obvious result. However, one of the reasons for this exercise is to provide practice at properly writing a proof that one set is a subset of another set. So we should start the proof by assuming that $A \subseteq B$ and $B \subseteq C$. Then we should choose an arbitrary element of $A$.

To prove the following set equalities, it may be necessary to use some of the properties of positive and negative real numbers. For example, it may be necessary to use the facts that:

• The product of two real numbers is positive if and only if the two real numbers are either both positive or both negative. - The product of two real numbers is negative if and only if one of the two numbers is positive and the other is negative.

For example, if $x \left( x - 2 \right) \lt 0$, then we can conclude that either (1) $x \lt 0$ and $x - 2 > 0$ or (2) $x > 0$ and $x - 2 \lt 0$. However, in the first case, we must have $x \lt 0$ and $x > 2$, and this is impossible. Therefore, we conclude that $x > 0$ and $x - 2 \lt 0$, which means that $0 \lt x \lt 2$.

Use the choose-an-element method to prove each of the following:

$\left\{x \in \mathbb{R} \mid x^2 - 3x - 10 \lt 0 \right\} = \left\{ x \in \mathbb{R} \mid -2 \lt x \lt 5 \right\}$

To prove the following set equalities, it may be necessary to use some of the properties of positive and negative real numbers. For example, it may be necessary to use the facts that:

• The product of two real numbers is positive if and only if the two real numbers are either both positive or both negative. - The product of two real numbers is negative if and only if one of the two numbers is positive and the other is negative.

For example, if $x \left( x - 2 \right) \lt 0$, then we can conclude that either (1) $x \lt 0$ and $x - 2 > 0$ or (2) $x > 0$ and $x - 2 \lt 0$. However, in the first case, we must have $x \lt 0$ and $x > 2$, and this is impossible. Therefore, we conclude that $x > 0$ and $x - 2 \lt 0$, which means that $0 \lt x \lt 2$.

Use the choose-an-element method to prove each of the following:

$\left\{x \in \mathbb{R} \mid x^2 - 5x + 6 \lt 0 \right\} = \left\{ x \in \mathbb{R} \mid 2 \lt x \lt 3 \right\}$

To prove the following set equalities, it may be necessary to use some of the properties of positive and negative real numbers. For example, it may be necessary to use the facts that:

• The product of two real numbers is positive if and only if the two real numbers are either both positive or both negative. - The product of two real numbers is negative if and only if one of the two numbers is positive and the other is negative.

For example, if $x \left( x - 2 \right) \lt 0$, then we can conclude that either (1) $x \lt 0$ and $x - 2 > 0$ or (2) $x > 0$ and $x - 2 \lt 0$. However, in the first case, we must have $x \lt 0$ and $x > 2$, and this is impossible. Therefore, we conclude that $x > 0$ and $x - 2 \lt 0$, which means that $0 \lt x \lt 2$.

Use the choose-an-element method to prove each of the following:

$\left\{ x \in \mathbb{R} \mid x^2 \geq 4 \right\} = \left\{ x \in \mathbb{R} \mid x \leq -2 \right\} \cup \left\{ x \in \mathbb{R} \mid x \geq 2 \right\}$