| Step 1. Read the problem. |
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| Step 2. Identify what we are looking for. |
We are looking for two consecutive integers. |
| Step 3. Name what we are looking for. |
Letn=the first integern+1=the next consecutive integer |
| Step 4. Translate into an equation. Restate the problem in a sentence. |
The product of the two consecutive integers is 132. |
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The first integer times the next integer is 132. |
| Translate to an equation. |
n(n+1)=132 |
| Step 5. Solve the equation. |
n2+n=132 |
| Bring all the terms to one side. |
n2+n−132=0 |
| Factor the trinomial. |
(n−11)(n+12)=0 |
| Use the zero product property. Solve the equations. |
n−11n==011n+12n==0−12 |
| There are two values for n that are solutions to this problem. So there are two sets of consecutive integers that will work. |
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| If the first integer isn=11then the next integer isn+111+112If the first integer isn=−12then the next integer isn+1−12+1−11 |
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| Step 6. Check the answer. |
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| The consecutive integers are 11,12 and −11,−12. The product 11⋅12=132 and the product −11(−12)=132. Both pairs of consecutive integers are solutions. |
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| Step 7. Answer the question. The consecutive integers are 11,12 and −11,−12. |
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