다항식 전체 문제

${\left(-\frac{3}{4}\right)}^{3}$

${x}^{-3}{x}^{4}$

$\frac{{5}^{6}}{{5}^{8}}$

${(47{a}^{18}{b}^{23}{c}^{5})}^{0}$

${4}^{-1}$

${(2y)}^{-3}$

${p}^{-3}\cdot {p}^{-8}$

$\frac{{x}^{4}}{{x}^{-5}}$

${(3{x}^{-3})}^{2}$

$\frac{24{r}^{3}s}{6{r}^{2}{s}^{7}}$

${\left(\frac{{x}^{4}{y}^{9}}{{x}^{-3}}\right)}^{2}$

$(8x{y}^{3})(-6{x}^{4}{y}^{6})$

$4u({u}^{2}-9u+1)$

$(m+3)(7m-2)$

$(n-8)({n}^{2}-4n+11)$

${(4x-3)}^{2}$

$(5x+2y)(5x-2y)$

$(15x{y}^{3}-35{x}^{2}y)\div 5xy$

$(3{x}^{3}-10{x}^{2}+7x+10)\div (3x+2)$

Use the Factor Theorem to determine if $x+3$ a factor of ${x}^{3}+8{x}^{2}+21x+18.$